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Concave and convex mirrors – Notes and Questions & Answers

POSITION OF IMAGE IN CASE OF CONCAVE MIRROR

Position of imagePosition of objectSize of imageNature of image
At infinityAt focus FHighly diminished, point sizeReal and inverted
Beyond CBetween F and CDiminishedReal and inverted
At CAt CSame sizeReal and inverted
Between C and FBeyond CEnlargedReal and inverted
At FAt infinityHighly enlargedReal and inverted
Between F and PBehind the mirrorEnlargedVirtual and erect

POSITION OF IMAGE IN CASE OF CONVEX MIRROR

Position of imagePosition of objectSize of imageNature of image
At infinityAt focus F behind the mirrorHighly diminished, point sizeVirtual and erect
Between infinity and PBetween P and F behind the mirrorDiminishedVirtual and erect

Mirror Equation, sign convention and magnification formula for concave and convex mirror

Mirror equation for concave and convex mirror

Formula is same for concave and convex mirror but sign convention has to be used carefully

Concave MirrorConvex Mirror
Focal Length ( f)Negative (-) Focus is in frontPositive (+) Focus is behind
object distance (u)Negative (-) (Always placed in front)Negative (-) (Always placed in front)
image distance (v)Negative (-) for Real images
Positive (+) for Virtual images
Always Positive (+) (Images are always virtual and behind)

NUMERICAL QUESTIONS ON CONCAVE MIRRORS

Position of image, object, focal length calculation using the Mirror Equation

  • An object is placed 2 m in front of a concave mirror of focal length 1.5 m. The position of image will be?

Answer: – 6 m.(u = -2, f = -1.5) Image formed is Beyond C, Real & Inverted, and Enlarged

  • An object placed 20 cm from the pole of a concave mirror forms real image at 60 cm from the pole. Focal length of the mirror is?

Answer: -15 cm.(u = -20, v = -60) Image formed is Beyond C, Real & Inverted, and Enlarged

  • An object is placed 15 cm from a concave mirror having focal length of 10 cm. The position of image will be?

Answer: -30 cm. (u = -15, f = -10)Image formed is Beyond C, Real & Inverted, and Enlarged

  • If object distance is 36 cm in front of a concave mirror of focal length 18 cm, where will the image be formed?

Answer: -36 cm. (u = -36, f = -18) Image is formed at C, Real & Inverted, and Enlarged

  • If object distance is 24 cm in front of a concave mirror of focal length 12 cm, where will the image be formed?

Answer: -24 cm. (u = -24, f = -12) Image is formed at C, Real & Inverted, and Enlarged

  • If object distance is 16 cm in front of a concave mirror of focal length 8 cm, where will the image be formed?

Answer: -16 cm. (u = -16, f = -8) Image is formed at C, Real & Inverted, and Enlarged

  • What is the focal length of a concave mirror if an object placed at 18 cm produces image at 6 cm in front of the mirror?

Answer: -4.5 cm. (u = -18, v = -6) Image is formed between C and F, Real & Inverted, Diminished

  • What is the focal length of a concave mirror if an object placed at 20 cm produces image at 5 cm in front of the mirror?

Answer: -4 cm. (u = -20, v = -5) Image is formed between C and F, Real & Inverted, Diminished

  • If an object is placed at 18 cm in front of a concave mirror of focal length 6 cm. The image will be formed at?

Answer: -9 cm. (u = -18, f = -6) Image is formed between C and F, Real & Inverted, Diminished

  • If object is placed at 6 cm in front of a concave mirror of focal length of 10 cm, the position of the image is?

Answer: +15 cm. (u =-6, f = -10) Image is formed behind mirror, Virtual & Erect, Enlarged

  • If object is placed at 4 cm in front of a concave mirror of focal length of 8 cm, the position of the image is?

Answer: +8 cm. (u =-4, f = -8) Image is formed behind mirror, Virtual & Erect, Enlarged

  • If object is placed at 5 cm in front of a concave mirror of focal length of 10 cm, the position of the image is?

Answer: +10 cm. (u =-5, f = -10) Image is formed behind mirror, Virtual & Erect, Enlarged

Magnification

  • Calculate the magnification of an object kept 20 cm in front of a concave mirror which forms an image 60 cm in front of it.

Answer: -3. (u = -20, v = -60)  Image formed is Real & Inverted, Three times enlarged

  • Calculate the magnification of an object kept 10 cm in front of a concave mirror forms an image 30 cm in front of it.

Answer: -3. (u = -10, v = -30) Image formed is Real & Inverted, Three times enlarged

  • Calculate the magnification of an object kept 15 cm in front of a concave mirror forms an image 45 cm in front of it.

Answer: -3. (u = -15, v = -45)  Image formed is Real & Inverted, Three times enlarged

  • If the image is formed at a distance of 6 cm and object is at 12 cm in front of a concave mirror, find the magnification?

Answer: -0.5. (u = -12, v = -6)Image is real & Inverted, Diminished by half

  • If the image is formed at a distance of 7 cm and object is at 14 cm in front of a concave mirror, find the magnification?

Answer: -0.5. (u = -14, v = -7) Image is real & Inverted, Diminished by half

  • If the image is formed at a distance of 8 cm and object is at 16 cm in front of a concave mirror, find the magnification?

Answer: -0.5. (u = -16, v = -8)   Image is real & Inverted, Diminished by half

  • If an object is placed 4 cm in front of a concave mirror and a virtual image is formed 8 cm behind the mirror find the magnification?

Answer: +2. (u = -4, v = -8) Image is Virtual & Erect, 2 times enlarged

NUMERICAL QUESTIONS ON CONVEX MIRRORS

Position of image, object, focal length calculation using the Mirror Equation

  • An object is placed at a distance of 10 cm from the pole of a convex mirror of focal length 15 cm. The image will be formed at?

Answer: +6 cm.  (u = -10, f = +15) Image is formed behind the mirror, Virtual & Erect, Diminished

  • An object is placed at a distance of 10 cm from the pole of a convex mirror with radius of curvature of 30 cm. Image will be formed at?

Answer:  +6 cm. (u = -10, f = +15) Image is formed behind the mirror, Virtual & Erect, Diminished

  • An object is placed at a distance of 8 cm from the pole of a convex mirror of focal length 12 cm. The image will be formed at?

Answer: +4.8 cm. (u = -8, f = +12) Image is formed behind the mirror, Virtual & Erect, Diminished

  • Find the position of the image of an object placed at a distance of 6 m from a convex mirror of focal length 2 m.

Answer: +1.5 m. (u = -6, f = +2) Image formed behind the mirror is, Virtual & Erect, Diminished

  • Find the position of the image of an object placed at a distance of 6 m from a convex mirror of focal length 4 m.

Answer: +2.4 m. (u = -6, f = +4) Image formed behind the mirror is, Virtual & Erect, Diminished

  • Find the position of the image of an object placed at a distance of 6 m from a convex mirror of focal length 3 m.

Answer: +2 m. (u = -6, f = +3) Image formed behind the mirror is, Virtual & Erect, Diminished

  • A rear view convex mirror has a radius of curvature of 6 m. If a car is located at 7 m from it, the position of the image is?

Answer: +2.1 m. (u = -7, f = +3) Image formed behind the mirror is, Virtual & Erect, Diminished

  • A rear view convex mirror has a radius of curvature of 4 m. If a car is located at 8 m from it, the position of the image is?

Answer: +1.6 m. (u = -8, f = +2) Image formed behind the mirror is, Virtual & Erect, Diminished

  • A rear view convex mirror has a radius of curvature of 4 m. If a car is located at 6 m from it, the position of the image is?

Answer: +1.5 m. (u = -6, f = +2) Image formed behind the mirror is, Virtual & Erect, Diminished

Magnification

  • Find the magnification if an object kept 30 cm in front of a convex mirror produces virtual image at 12 cm behind the mirror.

Answer: +0.4. (u = -30; v = +12) Image is Virtual & Erect, Diminished by 2/5th

  • Find the magnification if an object kept 20 cm in front of a convex mirror produces virtual image at 8 cm behind the mirror.

Answer: +0.4. (u = -20; v = +8)  Image is Virtual & Erect, Diminished by 2/5th

  • Find the magnification if an object kept 15 cm in front of a convex mirror produces virtual image at 6 cm behind the mirror.

Answer: +0.4. (u = -15; v = +6)  Image is Virtual & Erect, Diminished by 2/5th